# Java Find Square Root Example

If you need to find the square root of a number in your Java program, you can use the Math.sqrt() method that comes with Java. The method will return the correctly rounded positive square root of a double value. This method takes a double as the single argument and returns a double as the result.

There are a few special circumstances that may come up with using the sqrt() method.

• If the argument is NaN or less than zero, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is positive zero or negative zero, then the result is the same as the argument.

### Java Find Square Root Example Source Code

```package com.jcd.java.tutorials;

public class JavaMathSquareRoot
{

public static void main(String[] args)
{

System.out.println("Square root of 3: "+Math.sqrt(3));
System.out.println("Square root of 6: "+Math.sqrt(6));
System.out.println("Square root of 9: "+Math.sqrt(9));
System.out.println("Square root of 12: "+Math.sqrt(12));
System.out.println("Square root of 81: "+Math.sqrt(81));
System.out.println("Square root of 100: "+Math.sqrt(100));
}

}
```

### Java Find Square Root Example Output

```Square root of 3: 1.7320508075688772
Square root of 6: 2.449489742783178
Square root of 9: 3.0
Square root of 12: 3.4641016151377544
Square root of 81: 9.0
Square root of 100: 10.0
```