Java Find Square Root Example

If you need to find the square root of a number in your Java program, you can use the Math.sqrt() method that comes with Java. The method will return the correctly rounded positive square root of a double value. This method takes a double as the single argument and returns a double as the result.

There are a few special circumstances that may come up with using the sqrt() method.

  • If the argument is NaN or less than zero, then the result is NaN.
  • If the argument is positive infinity, then the result is positive infinity.
  • If the argument is positive zero or negative zero, then the result is the same as the argument.

Java Find Square Root Example Source Code


public class JavaMathSquareRoot 

	public static void main(String[] args) 
		System.out.println("Square root of 3: "+Math.sqrt(3));
		System.out.println("Square root of 6: "+Math.sqrt(6));
		System.out.println("Square root of 9: "+Math.sqrt(9));
		System.out.println("Square root of 12: "+Math.sqrt(12));
		System.out.println("Square root of 81: "+Math.sqrt(81));
		System.out.println("Square root of 100: "+Math.sqrt(100));


Java Find Square Root Example Output

Square root of 3: 1.7320508075688772
Square root of 6: 2.449489742783178
Square root of 9: 3.0
Square root of 12: 3.4641016151377544
Square root of 81: 9.0
Square root of 100: 10.0

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