April 3, 2018

# Java Find Square Root Example

If you need to find the square root of a number in your Java program, you can use the **Math.sqrt() method** that comes with Java. The method will return the correctly rounded positive square root of a double value. This method takes a double as the single argument and returns a double as the result.

There are a few special circumstances that may come up with using the sqrt() method.

- If the argument is NaN or less than zero, then the result is NaN.
- If the argument is positive infinity, then the result is positive infinity.
- If the argument is positive zero or negative zero, then the result is the same as the argument.

### Java Find Square Root Example Source Code

package com.jcd.java.tutorials; public class JavaMathSquareRoot { public static void main(String[] args) { System.out.println("Square root of 3: "+Math.sqrt(3)); System.out.println("Square root of 6: "+Math.sqrt(6)); System.out.println("Square root of 9: "+Math.sqrt(9)); System.out.println("Square root of 12: "+Math.sqrt(12)); System.out.println("Square root of 81: "+Math.sqrt(81)); System.out.println("Square root of 100: "+Math.sqrt(100)); } }

### Java Find Square Root Example Output

Square root of 3: 1.7320508075688772 Square root of 6: 2.449489742783178 Square root of 9: 3.0 Square root of 12: 3.4641016151377544 Square root of 81: 9.0 Square root of 100: 10.0